Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you simplify #(2-2i)^2#?

1 Answer

Aug 10, 2018

#z=0-8i#

Explanation:

Let ,

#z=(2-2i)^2 ,where ,z inCC#

#:.z=4-8i+4i^2#

#:.z=4-8i+4(-1)to[because i^2=-1]#

#:.z=4-8i-4#

#:.z=0-8i#

Related questions

See all questions in Multiplication of Complex Numbers

Impact of this question

9582 views around the world

You can reuse this answer
Creative Commons License