What are the zeros of #f(x) = x^2-8x+16#?

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Answer 1 · 2018-08-10T05:52:24

#x=4# with multiplicity #2#

Given:

#f(x) = x^2-8x+16#

We can recognise this as a perfect square trinomial, since it has the form:

#A^2-2AB+B^2 = (A-B)^2#

with #A=x# and #B=4# ...

#x^2-8x+16 = x^2-2(x)(4)+4^2 = (x-4)^2#

So #f(x)# has one repeated zero #x=4# with multiplicity #2#.