How do you solve #6= - 3x + 33#?

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Answer 1 · 2016-11-30T03:32:07

#x = 9#

First, substract #33# from each side of the equation to isolate the #x# term and keep the equation balanced:

#6 - 33 = -3x + 33 - 33#

#-27 = -3x + 0#

#-27 = -3x#

Now, divide each side of the equation by #-3# to solve for #x# and keep the equation balanced:

#(-27)/(-3) = (-3x)/(-3)#

#9 = (cancel(-3)x)/(cancel((-3))#

#x = 9#

Answer 2 · 2016-11-30T03:33:41

#x = 9#

#6 = -3x + 33#
#6-33 = -3x + 33 -33#
#-27 = -3x#
#-27/-3 = -3x/-3#
#9 = x#

Answer 3 · 2018-08-10T02:41:55

#x=9#

Let's subtract #33# from both sides to get

#-3x=-27#

Our last step would be to divide both sides by #-3#, which gives

#x=9#

Hope this helps!