How do you solve #5( x + 6) - 2= 16#?

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Answer 1 · 2016-12-04T21:41:49

#x = -12/5#

First, expand the term in parenthesis:

#5x + 30 - 2 = 16#

Next consolidate like terms:

#5x + 28 = 16#

Next isolate the #x# term on one side of the equation while keeping the equation balanced:

#5x + 28 - 28 = 16 - 28#

#5x + 0 = - 12#

#5x = -12#

Now, solve for #x# while keeping the equation balanced:

#(5x)/5 = (-12)/5#

#(cancel(5)x)/cancel(5) = -12/5#

#x = -12/5#

Answer 2 · 2018-08-10T02:25:33

#x=-12/5#

We can start by distributing the #5# on the left side to get

#5x+30-2=16#

We can further simplify the constants on the left to get

#5x+28=16#

Next, let's subtract #28# from both sides to get

#5x=-12#

Lastly, we can divide both sides by #5# to get

#x=-12/5#

Hope this helps!