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How do you sketch the angle in standard position #(2pi)/9#?

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A. S. Adikesavan

Aug 9, 2018

See graph and and explanation.

Explanation:

The direction angle #theta = 2/9pi = (2/9(180)^o = 40^o#.

The Cartesian #P ( 1, tan 40^o ) = ( 1, 0.8391 )#.

In polar coordinates, it is #P ( OP, 40^o )#

#= P ( sqrt ( 1^2 + (0.8391)^2), 40^o ) = P ( 1.2054, 40^o )#. See grapk.

graph{(arctan(y/x) - 2/9pi)((x-1)^2 + (y- tan(2/9pi))^2-0.0005)=0[0 2 0 1]}

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