A force 6i+3j+k displaces an object from A(0,3,2) to B(5,1,6) what is the work done?

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Answer 1 · 2018-08-09T06:41:43

The work done is $=28J$

The work is the dot product of force and distance

The force is

$vecF=<6,3,1>$

The displacement is

$vec(AB)= <5-0, 1-3, 6-2> = <5, -2,4>$

The work is

$W=vecF.vec(AB) = <6,3,1> . <5, -2,4>$

$=(6xx5)+(3xx -2)+(1xx 4)$

$=30-6+4$

$=28J$