How do you graph #2x+3y>=280#?

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Answer 1 · 2018-08-08T00:51:53

Refer to the explanation.

Graph:

#2x+3y>=280#

Find the x- and y-intercepts.

Make both sides equal in order to find the intercepts.

X-intercept: value of #x# when #y=0#.

Substitute #0# for #y# and solve for #x#.

#2x+3(0)=280#

#2x=280#

Divide both sides by #2#.

#x=280/2#

#x=140#

The x-intercept is #(140,0)#. Plot this point.

Y-intercept: value of #y# when #x=0#

#2(0)+ 3y=280#

#3y=280#

Divide both sides by #3#.

#y=280/3# or #~~93.33#

The y-intercept is #(0,280/3)# or #(0,~~93.33)#. Plot this point.

Since the relationship between both sides is #>=#, draw a straight, solid line through the points. Then shade in the area above the line.

graph{y>=-2/3x+280/3 [-10, 10, -5, 5]}