A particle is moving in a straight line.its displacement at time t is given by s (in m) =-4t^2+2t,then its velocity and acceleration at time t=1/2 second are..???

1 Answer
Aug 7, 2018

Please see the explanation below.

Explanation:

The displacement is

s(t)=-4t^2+2t

The velocity is the derivative of the displacement

So,

v(t)=(ds)/dt=-8t+2

And when the time is t=1/2s, the velocity is

v(1/2)=-8*1/2+2=-4+2=2ms^-1

The acceleration is the derivative of the velocity

a(t)=(dv)/dt=-8ms^-2

The acceleration is constant whaever the value of t