How do you multiply ${[(2 z + r) + 1]}^{2}$ $[(2z + r) +1]^2$ ?

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How do you multiply ${[(2 z + r) + 1]}^{2}$ $[(2z + r) +1]^2$ ?

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Answer 1 · 2018-08-06T10:47:00

$4 z^{2} + r^{2} + 4 z r + 4 z + 2 r + 1$ $4z^2+r^2+4zr+4z+2r+1$

Explanation:

${[(2 z + r) + 1]}^{2} = ((2 z + r) + 1) ((2 z + r) + 1)$ $[(2z+r)+1]^2=((2z+r)+1)((2z+r)+1)$

$expand factors using FOIL$ $"expand factors using FOIL"$

$= {(2 z + r)}^{2} + 2 (2 z + r) + 1$ $=(2z+r)^2+2(2z+r)+1$

$= 4 z^{2} + 4 z r + r^{2} + 4 z + 2 r + 1$ $=4z^2+4zr+r^2+4z+2r+1$

$= 4 z^{2} + r^{2} + 4 z r + 4 z + 2 r + 1$ $=4z^2+r^2+4zr+4z+2r+1$

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How do you multiply ${[(2 z + r) + 1]}^{2}$ $[(2z + r) +1]^2$ ?

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