How do you multiply #[(2z + r) +1]^2#?
1 Answer
Aug 6, 2018
Explanation:
#[(2z+r)+1]^2=((2z+r)+1)((2z+r)+1)#
#"expand factors using FOIL"#
#=(2z+r)^2+2(2z+r)+1#
#=4z^2+4zr+r^2+4z+2r+1#
#=4z^2+r^2+4zr+4z+2r+1#
