How do you solve # -x -11 = x-19#?

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Answer 1 · 2017-02-04T19:07:23

See the entire solution process below:

First, add #color(red)(x)# and #color(blue)(19)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-x - 11 + color(red)(x) + color(blue)(19) = x - 19 + color(red)(x) + color(blue)(19)#

#-x + color(red)(x) - 11 + color(blue)(19) = x + color(red)(x) - 19 + color(blue)(19)#

#0 + 8 = 2x - 0#

#8 = 2x#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#8/color(red)(2) = (2x)/color(red)(2)#

#4 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#4 = x#

#x = 4#

Answer 2 · 2018-08-06T03:07:03

#x=4#

We can start by adding #11# to both sides to get

#-x=x-8#

Next, we can subtract #x# from both sides to get

#-2x=-8#

Lastly, we can divide both sides by #-2# to get

#x=4#

Hope this helps!