The ratio of electric force betweem 2 electrons to the gravotational force between them is of the order of?

Question

1257 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-08-04T15:04:15

let the distance between them to be $r$

$F_g=(Gm_1m_2)/(r^2)$

$F_c=(Kq_1q_2)/r^2$

From a google search we find

$q_e=1.6*10^-19 C$
$m_e=9.1*10^-31 Kg$
$G=6.67*10^-11 m^3/(Kgs^2)$
$K=9*10^9 (Nm^2)/C^2$

$F_c/F_g=[Kq^2]/[Gm^2]$ $=(9*10^9*2.56*10^-38*10^11*10^62)/(6.67*82.81)$

$=0.0417*10^44$ a very big number because electrons have extremly small mass