What is #12x-4y=-8# written in slope-intercept form?

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Answer 1 · 2018-08-03T13:52:10

See a solution process below:

The slope-intercept form of a linear equation is: #y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

Solving this equation for #y# gives:

#12x - 4y = -8#

#-color(red)(12x) + 12x - 4y = -color(red)(12x) - 8#

#0 - 4y = -12x - 8#

#-4y = -12x - 8#

#(-4y)/color(red)(-4) = (-12x - 8)/color(red)(-4)#

#(color(red)(cancel(color(black)(-4)))y)/cancel(color(red)(-4)) = (-12x)/color(red)(-4) - 8/color(red)(-4)#

#y = 3x - (-2)#

#y = color(red)(3)x + color(blue)(2)#

Answer 2 · 2018-08-03T14:12:51

#color(crimson)(y = 3 x + 2#

Slope = m = 3, y-intercept = c = 2#

Slope- intercept form of equation #y = m x + c#

#12x - 4y = -8#

#12x + 8 = 4y#

#y = (12/4)x + (8/2)#

#color(crimson)(y = 3 x + 2#

Slope = m = 3, y-intercept = c = 2#