What is the equation of the line passing through the points $(4, - 5)$ $(4, -5)$ and $(2, - 7)$ $(2,-7)$ ?

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Answer 1 · 2018-08-02T10:01:27

$y = x - 9$ $y=x-9$

First you need to find the gradient of the line

$m = \frac{- 5 + 7}{4 - 2} = \frac{2}{2} = 1$ $m=(-5+7)/(4-2)=2/2=1$

Then, using the point gradient formula

$y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$
where $(x_{1}, y_{1})$ $(x_1,y_1)$ can be either point and $m$ $m$ is the gradient

So, I'm using the point $(4, - 5)$ $(4,-5)$

$(y + 5) = 1 (x - 4)$ $(y+5)=1(x-4)$

$y + 5 = x - 4$ $y+5=x-4$

$y = x - 9$ $y=x-9$

What is the equation of the line passing through the points (4,−5)(4, -5) and (2,−7)(2,-7)?