How do you simplify #4sqrt32*sqrt2#?

Question

1670 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-25T21:19:28

See a solution process below:

To simplify this expression use this rule for radicals:

#sqrt(color(red)(a)) * sqrt(color(blue)(b)) = sqrt(color(red)(a) * color(blue)(b))#

#4sqrt(color(red)(32)) * sqrt(color(blue)(2)) =>#

#4sqrt(color(red)(32) * color(blue)(2)) =>#

#4sqrt(64) =>#

#4 * 8 =>#

#32#

Answer 2 · 2018-07-25T21:19:40

#32#

#4sqrt(16*2)*sqrt2= 4*4*sqrt2*sqrt2= 32#