How much energy would be absorbed as heat by 75g of iron when heated from 295k to 301k? c=.46

1 Answer
Meave60
Jul 24, 2018

#"210 Joules"# of heat energy are required.

Explanation:

Equation:

#q=mcDeltaT#,

where:

#q# is energy, #m# is mass, #c# is specific heat capacity, and #DeltaT# is change in temperature. #DeltaT=T_"final"-T_"initial"#

Known

#c="0.46 J/g"*"K"#

#m="75 g"#

#DeltaT="301 K"-"295 K"="6 K"#

Unknown

energy, #q#

Plug the known values into the equation and solve.

#q=75color(red)cancel(color(black)("g"))xx0.46("J")/(color(red)cancel(color(black)("g"))*color(red)cancel(color(black)("K")))xx6color(red)cancel(color(black)("K"))="210 J"# (rounded to two significant figures)

#"210 Joules"# of heat energy are required.

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