In a house, 5 bulbs of 40W, 4 bulbs of 1000 W and 750W refrigerator are used for 5 hours daily. Thn how much energy is consumed per day?

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Answer 1 · 2018-07-23T16:36:54

The energy consumed daily is $=24.75kWh$

The power installed is

$P=(5*40)+(4*1000)+(750)=4950W$

The time is

$t=5h$

The energy consumed daily is

$E=Pt=4950*5=24750Wh=24.75kWh$

Answer 2 · 2018-07-23T16:49:58

The energy consumed per day is $24.75 "kiloWatt" * "hours"$ .

Adding those power ratings together:

$5*40 W + 4*1000 W + 1*750 W = 4950 W$

The power company measures energy in $"kiloWatt" * "hours"$ .

Multiplying the power total by the 5 hours gives us the energy consumed per day:

$4.95 "kiloWatt" * 5 "hours" = 24.75 "kiloWatt" * "hours"$

I hope this helps,
Steve