How do you find the inverse of $f (x) = {(x - 4)}^{2}$ $f(x)=(x-4)^2$ ?

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How do you find the inverse of $f (x) = {(x - 4)}^{2}$ $f(x)=(x-4)^2$ ?

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Answer 1 · 2018-07-20T17:50:06

The inverse of this function is $f (x) = \sqrt{x} + 4$ $f(x)=sqrtx+4$

Explanation:

Considering $f (x) = y$ $f(x)=y$ , to find the inverse function, the $x$ $x$ and $y$ $y$ values are switched giving the new equation of
$x = {(y - 4)}^{2}$ $x=(y-4)^2$

Then solve for $y$ $y$
$\sqrt{x} = y - 4$ $sqrtx=y-4$

$y = \sqrt{x} + 4$ $y=sqrtx+4$

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How do you find the inverse of $f (x) = {(x - 4)}^{2}$ $f(x)=(x-4)^2$ ?

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How do you find the inverse of $f (x) = {(x - 4)}^{2}$ $f(x)=(x-4)^2$ ?