How do you solve #x-4/x-1 = 12/3-x +1#?

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solving rational equations

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Answer 1 · 2018-07-20T04:29:28

#x=(3+sqrt17)/2# or #x=(3-sqrt17)/2#

#x-4/x-1=12/3-x+1# where #x!=0#

#x-4/x-1=4-x+1#

#2x-6=4/x#

#2x^2-6x=4#

#2x^2-6x-4=0#

#x^2-3x-2=0#

#x=(3+-sqrt(9+8))/2#

#x=(3+-sqrt17)/2#

#x=(3+sqrt17)/2# or #x=(3-sqrt17)/2#