How do you evaluate #(1+ 3i ) - ( 5+ 9i )#?

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Answer 1 · 2018-07-17T14:58:38

#-4-6i#

1) Remove brackets:
#1+3i-5-9i#

2) Add real numbers to real numbers and complex numbers to complex numbers:
#-4-6i#

Answer 2 · 2018-07-17T14:59:15

#-4-6i#

Just separate real & imaginary parts & add/subtract them as follows

#(1+3i)-(5+9i)#

#=1+3i-5-9i#

#=1-5+3i-9i#

#=-4-6i#