How many ounces of pure water would have to be added to 30 ounces of 30% solution of alcohol to reduce the original solution to 25%?

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Answer 1 · 2018-07-16T12:35:43

#6# ounces of pure water added to #30# ounces #30%# alcohol solution to get #36# ounces of #25%#solution.

Let #x# ounces of pure water is added to #30# ounces #30%#

alcohol solution to reduce it to #25%# solution. Balancing alcohol

content ,we get #x*0+ 30* 30/cancel100= (x+30)*25/cancel100#

or #900 = 25 x +750 or 25 x = 900-750 or 25 x =150#

#:. x=150/25=6# ounce. Hence #6# ounces of pure water added

to #30# ounces #30%# alcohol solution to get #36# ounces of

#25%# solution. [Ans]