How do you solve the system of inequalities #3x-4y<=12# and #-2x+5y>=10#?

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Answer 1 · 2018-07-16T12:05:51

#y>=min(2+2/5x,-3+3/4x)#

Solving the first inequality for #y#

subtracting #3x# we get

#-4y<=12-3x#

dividing by #-4#

#y>=-3+3/4x#
solving the second inequality for #y#

adding #2x#

#5y>= 10+2x#

dividing by #5#

#y>=2+2/5x#
so

#y>=2+2/5x#

and

#y>=min(2+2/5x,-3+3/4x)#