How do you solve #y= 7x + 2# and #y = - 3x - 8#?

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Answer 1 · 2018-07-14T16:00:00

#x=-1,y=-5#

Both equations must be equal, so we get

#7x+2=-3x-8#

adding #-2# on both sides and adding #3x#
so

#10x=-10#

so #x=-1# and #y=3-8=-5#

Answer 2 · 2018-07-14T16:22:21

#x=-1# and #y=-5#

Since we are being told #y# equals two things, we can equate them.

#7x+2=-3x-8#

Let's get our variables on the left, and our constants on the right. We can add #3x# to both sides and subtract #2# from both sides.

#10x=-10#

Isolating #x#, we get

#x=-1#

We can plug this into either equation to solve for #y#. Let's use the first one:

#y=7(-1)+2=2-7=-5#

We get

#x=-1# and #y=-5#

Hope this helps!