How do you multiply and simplify #(\frac { 2y ^ { 0} \cdot x ^ { 2} } { ( x ^ { - 1} ) ^ { - 4} } ) ^ { 3}#?

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Answer 1 · 2018-07-11T12:18:16

#8/x^6#

we have

#(2y^0)/(x^(-1))^(-4)=(2x^2)/x^4=2/x^2#
Now we get

#(2/x^2)^3=2^3/x^6=8/x^6#

Answer 2 · 2018-07-11T12:21:39

#\frac{8}{x^6}#

Given that

#(\frac{2y^0\cdot x^2}{(x^{-1})^{-4}})^3#

#( \frac{2(1)\cdot x^2}{x^{-1\times -4} ))^3#

#=(\frac{2x^2}{x^4})^3#

#=(\frac{2}{x^{4-2}})^3#

#=(2/x^2)^3#

#=\frac{2^3}{(x^2)^3}#

#=\frac{8}{x^6}#