How do you evaluate $- 5 - - 4 \frac{1}{4} + 3 \frac{1}{4} + - 6$ $-5- - 4\frac { 1} { 4} + 3\frac { 1} { 4} + - 6$ ?

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How do you evaluate $- 5 - - 4 \frac{1}{4} + 3 \frac{1}{4} + - 6$ $-5- - 4\frac { 1} { 4} + 3\frac { 1} { 4} + - 6$ ?

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Answer 1 · 2018-07-10T00:58:10

$- 3 \frac{1}{2}$ $-3 1/2$

Explanation:

Let's simplify the addition / subtraction signs first. Here's a simple rule,
BBC-Two signs

$- 5 - - 4 \frac{1}{4} + 3 \frac{1}{4} + - 6$ $-5- -4 1/4+3 1/4 + -6$
= $- 5 + 4 \frac{1}{4} + 3 \frac{1}{4} - 6$ $-5color(red)+4 1/4+3 1/4color(red) -6$

Next step is to convert all number to improper fractions to make adding and subtracting easy. We'll keep 4 as the denominator (number at the bottom).

= $- \frac{20}{4} + \frac{17}{4} + \frac{13}{4} - \frac{24}{4}$ $-20/4+17/4+13/4 -24/4$

= $\frac{- 20 + 17 + 13 - 24}{4}$ $(-20+17+13-24)/4$

= $- \frac{14}{4}$ $-14/4$

= $- 3 \frac{2}{4}$ $-3 2/4$ (convert to mixed fraction)

= $- 3 \frac{1}{2}$ $-3 1/2$ (simplify 2/4 to 1/2)

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How do you evaluate $- 5 - - 4 \frac{1}{4} + 3 \frac{1}{4} + - 6$ $-5- - 4\frac { 1} { 4} + 3\frac { 1} { 4} + - 6$ ?

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