People in Japan on average eat 3 ounces of fish per day. How many pounds of fish is this per week?

1 Answer
Jul 9, 2018

#5.6875/1("pound")/("week") -> 5.6875" pounds per week"#

Explanation:

#color(brown)("Did you know that you cam manipulate units of measurement")##color(brown)("the same way you can numbers")#

First lets count this in ounces per week

Consider just the units of measurement to start with.

We need ounces per week #->("ounces")/("week")#

We have got: #("ounces")/("day")# so we need to change this by replacing the unit of day with the unit of week.

#("ounces")/(cancel("day"))xx(cancel("days"))/("week") = ("ounces")/("week")#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("We do the same thing with the numbers")#

#[13/1 ("ounces")/(cancel("day"))]xx[7/1 (cancel("days"))/("week")] = 91/1 ("ounces")/("week")" "..Eqn(1)#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(brown)("Converting this to pounds")#

There are 16 ounces in 1 pound #->16/1 ("ounces")/("pound")" "..Eqn(2)#

So to covert #("ounces")/("week")# into #("pounds")/("week")# we can turn #Eqn(2)# upside

down and multiply. Like this:

#color(white)("d")Eqn(1)color(white)("dddd")xxcolor(white)("ddd")1/(Eqn(2))#

# 91/1 (cancel("ounces"))/("week")color(white)("d")xxcolor(white)("d")1/16 ("pounds")/(cancel("ounces")) color(white)("d")=color(white)("d")91/16 ("pound")/("week")#

But we need 1 week. So divide both top and bottom by 16

#(91-:16)/(16-:16) ("pound")/("week") color(white)("dddd")=color(white)("dddd") 5.6875/1("pound")/("week")#