B) Calculate the energy required to heat up 50 kg of aluminium from 200C to 3000C. The specific heat capacity is 913 J/kg K. ?

1 Answer
Nam D.
Jul 9, 2018

I make it approximately #140.29# megajoules.

Explanation:

We use the specific heat equation, which states that,

#q=mcDeltaT#

where:

  • #q# is the heat energy supplied in joules

  • #m# is the mass of the object in kilograms

  • #c# is the specific heat capacity of the object, here it's in joules per kilogram kelvin

  • #DeltaT# is the change in temperature

Here, #DeltaT=3000^@"C"-200^@"C"=2800^@"C"=3073.15 \ "K"#.

So, we get:

#q=50color(red)cancelcolor(black)"kg"*(913 \ "J")/(color(red)cancelcolor(black)"kg"color(red)cancelcolor(black)"K")*3073.15color(red)cancelcolor(black)"K"#

#=140289298 \ "J"#

#~~140.29 \ "MJ"#

Now that's a lot of heat energy!

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