How many electron would have to ejected from a body to descrease its mass by 0.03 milligrams. The mass of one electron is 9.1*10 the minus 31kg?

Question

2284 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-08T15:49:38

Approximately #3.3*10^21# electrons.

The mass of an electron is:

#m_(e^-)=9.1*10^-31 \ "kg"#

Note that #1 \ "kg"-=1*10^6 \ "mg"#. So the mass of an electron in milligrams will be:

#m_(e^-)=9.1*10^-31color(red)cancelcolor(black)"kg"*(10^6 \ "mg")/(color(red)cancelcolor(black)"kg")=9.1*10^-25 \ "mg"#

In order to reduce the mass of a body by #0.03 \ "mg"=3*10^-2 \ "mg"#, then a total of:

#(3*10^-2color(red)cancelcolor(black)"mg")/(9.1*10^-25color(red)cancelcolor(black)"mg""/"e^-)~~3.3*10^21 \ e^-#

must be released.