How do you simplify #sqrt(12x^2)#?

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Answer 1 · 2018-07-07T15:20:01

#2|x|sqrt(3)#

Using that
#sqrt(ab)=sqrt(a)*sqrt(b)# for #a,b>=0#
and
#sqrt(x^2)=|x|# we get

#sqrt(4*x^2*3)=2|x|sqrt(3)#

Answer 2 · 2018-07-07T15:32:59

#2xsqrt3#

We can expand the radical as

#sqrt12*sqrt(x^2)#

The square root of something squared will just simplify to that something, and as for #sqrt12#, we can try to factor out a perfect square.

We can rewrite #sqrt12# as

#sqrt4*sqrt3#, which simplifies to #2sqrt3#.

Thus, we are left with #2sqrt3x#, or #2xsqrt3#

Hope this helps!