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Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 0.00009?

1 Answer

Jul 4, 2018

# log 0.00009 = -4.0458#

Explanation:

#log 0.00009 = log (10^-5 xx 9) #

#= log 10^-5 + log 9#

#= -5 + 0.9542 #

# = -4.0458#

Note:

#log (a xx b) = log a + log b#
#log_b b^n = n xx log_b b = n#

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