Determine the amount of water required to produce 500 ml of a solution that is 35% of alcohol dissolved in water?

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Answer 1 · 2018-07-04T07:25:38

325 mL

#%"(v/v)"="volume of solute"/"volume of solution"*100%#

From the question, alcohol is the solute and water is the solvent . Together, they combine to become solution .

Therefore,
#"volume of solute " = " volume of alcohol"#

#"volume of solution" = "volume of solute" + "volume in solvent" = "volume of alcohol" + "volume of water" = "500 mL"#

Plug in the given values into the percent volume formula to find the volume of alcohol,
#%"(v/v)"="volume of solute"/"volume of solution"*100%#

#35%="volume of alcohol"/"500 mL"*100%#

#"volume of alcohol" = ("35%"*"500 mL")/"100%"="175 mL"#

From the calculated volume of alcohol, we can now find the volume of water,

#"volume of solution" = "volume of alcohol" + "volume of water"#

#"500 mL" = "175 mL" + "volume of water"#

#"volume of water" = "500 mL" - "175 mL" = "325 mL"#