How do you multiply $\sqrt{81} \cdot \sqrt{36}$ $sqrt81*sqrt36$ ?

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Answer 1 · 2018-07-03T13:05:01

$\pm 54$ $+-54$

Given: $\sqrt{81} \cdot \sqrt{36}$ $sqrt81*sqrt36$

Use the fact that $sqrta*sqrtb=sqrt(ab) \ AAa,b>=0$ .

$=sqrt(81*36)$

$=sqrt(2916)$

$=sqrt(54^2)$

Now, use the fact that $sqrt(a^2)=+-a$ .

$=+-54$

Answer 2 · 2018-07-03T19:41:35

$sqrt(81) * sqrt(36) = +-54$

It can be done either of 2 ways: take square root first, then multiply
or multiply first, then take square root.

$sqrt(81) * sqrt(36) = +-9 * +-6 = +-54$

$sqrt(81) * sqrt(36) = sqrt(81*36) = sqrt(2916) = +-54$

I hope this helps,
Steve

How do you multiply sqrt81*sqrt36√81⋅√36sqrt81*sqrt36?