How do you factor $x^{3} - 9 x^{2} + 27 x - 27$ $x^3 - 9x^2 +27x - 27$ ?

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Answer 1 · 2018-07-02T16:36:59

${(x - 3)}^{3}$ $(x-3)^3$

$x^{3} - 9 x^{2} + 27 x - 27$ $x^3-9x^2+27x-27$

= $x^{3} - 27 - 9 x^{2} + 27 x$ $x^3-27-9x^2+27x$

= $(x - 3) (x^{2} + 3 x + 9) - 9 x (x - 3)$ $(x-3)(x^2+3x+9)-9x(x-3)$

= $(x - 3) \cdot (x^{2} + 3 x + 9 - 9 x)$ $(x-3)*(x^2+3x+9-9x)$

= $(x - 3) \cdot (x^{2} - 6 x + 9)$ $(x-3)*(x^2-6x+9)$

= $(x - 3) \cdot {(x - 3)}^{2}$ $(x-3)*(x-3)^2$

= ${(x - 3)}^{3}$ $(x-3)^3$

How do you factor x3−9x2+27x−27x^3 - 9x^2 +27x - 27?