An isosceles triangle has a base of 20 cm and legs measuring 36 cm. How long are the legs of a similar triangle with base measuring 50 cm?

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Answer 1 · 2018-07-02T15:12:54

#90# centimeters

Because both triangles are similar, we have:

#b_1/l_1=b_2/l_2#

where:

#b_1,b_2# are the bases of the first and second triangle, respectively

#l_1,l_2# are the legs of the first and second triangle, respectively

So, we get:

#(20 \ "cm")/(36 \ "cm")=(50 \ "cm")/l_2#

#l_2=(36color(red)cancelcolor(black)"cm")/(20color(red)cancelcolor(black)"cm")*50 \ "cm"#

#=1.8*50 \ "cm"#

#=90 \ "cm"#