How do you graph the inequality $4 x - 2 y < - 3$ $4x-2y<-3$ ?

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How do you graph the inequality $4 x - 2 y < - 3$ $4x-2y<-3$ ?

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Answer 1 · 2018-07-01T03:52:33

See below

Explanation:

$4 x - 2 y < - 3$ $4x-2y<-3$

Subtract $4 x$ $4x$ to both sides

$- 2 y < - 4 x - 3$ $-2y<-4x-3$

Divide through by $- 2$ $-2$ and change the direction of the inequality.

$y > 2 x + \frac{3}{2}$ $y>2x+3/2$

Now consider the limiting case where: $y = 2 x + \frac{3}{2}$ $y=2x+3/2$

This is the straight line with slope $2$ $2$ and $y -$ $y-$ intercept of $+ \frac{3}{2}$ $+3/2$

Then the graphic representation of the inequality is the area of all points where $y$ $y$ is greater than but not equal to values on this line. Shown as the shaded area below.

graph{4x-2y<-3 [-12.66, 12.65, -6.33, 6.33]}

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How do you graph the inequality $4 x - 2 y < - 3$ $4x-2y<-3$ ?

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