How do you solve the following linear system: $2 x + 3 y = - 1, 5 x + y = 8$ $2x+ 3y=-1 , 5x+y=8$ ?

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Answer 1 · 2018-06-30T23:42:46

$x=25/13,\ y=-21/13$

Given that

$2x+3y=-1\ .......(1)$

$5x+y=8\ .......(2)$

Multiplying (2) by $3$ on both sides & subtracting from (1), we get

$2x+3y-3(5x+y)=-1-3\times8$

$-13x=-25$

$x=25/13$

setting $x=25/13$ in (2), we get

$5(25/13)+y=8$

$y=8-125/13=-21/13$

How do you solve the following linear system: 2x+ 3y=-1 , 5x+y=8 2x+3y=−1,5x+y=8 2x+ 3y=-1 , 5x+y=8 ?