How do you solve $-\frac { 3} { 7} = - \frac { 1} { 3} u + \frac { 1} { 2}$ ?

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Answer 1 · 2018-06-30T20:09:47

$u=23/14$

$-3/7=-1/3u+1/2$

Multiply through by -3

$1/7=u-3/2$

Add 3/2 to both sides

$u=1/7+3/2=23/14$

Answer 2 · 2018-06-30T20:32:28

$u=23/14$

We want nothing in front of $u$ , so to start, we can multiply all terms by $-3$ . We now have the following equation:

$1/7-u=-3/2$

Let's subtract $1/7$ from both sides to get

$-u=-3/2-1/7$

We can have a common denominator of $14$ by multiplying the top and bottom of the first by $7$ , and the second top/bottom by $2$ . We get

$-u=-21/14-2/14=-23/14$

$-u=-23/14$

Dividing both sides by $-1$ gives us

$u=23/14$

Hope this helps!

How do you solve -\frac { 3} { 7} = - \frac { 1} { 3} u + \frac { 1} { 2}-\frac { 3} { 7} = - \frac { 1} { 3} u + \frac { 1} { 2}?