How do you graph #6x>=-1/3y# on the coordinate plane?

1 Answer
Tony B
Jun 30, 2018

See explanation

Explanation:

Given: #6x >= -1/3y#

Multiply both sides by (-1 )

#-6x <= 1/3ycolor(white)("dd")# Notice that the inequality has turned round.

Multiply both sides by 3

#-18x<=y#

Now plot the straight line graph of #y=-18x#

Draw any vertical line. #y# can and may take on any value above and on #y=-18x#

Example: suppose I pick on #x= 1/2# Then the brown line in the graph below represents all the feasible values for #y# at #x=1/2#

Lots and lots of these lines, when combined, give an 'area' on the graph (as shaded) that represents all the possible values of #y# for all the possible values of #x#.

Tony B

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