How many atoms of each element of #AgNO_3# are in 0.15 mol of #AgNO_3#?

1 Answer
Dr. K.
Jun 29, 2018

#9.0"x"10^22"Ag atoms"#

#9.0"x"10^22"N atoms"#

#2.7"x"10^23"O atoms"#

Explanation:

  1. From 0.15mol of #AgNO_3#, we can find the moles of each element by counting how many of each element is present in the entire compound. In #AgNO_3#, there's 1 Ag, 1 N and 3 O.
  2. Then, we convert from moles of each element to the number of atoms using Avogadro's number #6.02"x"10^23#.

I went ahead and set up the two steps above in 1 line for each element:
#"Ag atoms"=0.15 "mol " AgNO_3*(1 "mol " Ag)/(1 "mol " AgNO_3)*(6.02"x"10^23 "Ag atoms")/(1 "mol " Ag)=9.0"x"10^22"Ag atoms"#

#"N atoms"=0.15 "mol " AgNO_3*(1 "mol " N)/(1 "mol " AgNO_3)*(6.02"x"10^23 "N atoms")/(1 "mol " N)=9.0"x"10^22"N atoms"#

#"O atoms"=0.15 "mol " AgNO_3*(3 "mol " O)/(1 "mol " AgNO_3)*(6.02"x"10^23 "O atoms")/(1 "mol " O)=2.7"x"10^23"O atoms"#

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