Question 3 part 2 and 3 please?

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1 Answer
Jun 28, 2018

x_max=sqrt{m_1u²- [(m_1u)²] / [m_1+m_2]/k}

Explanation:

conservation of momentum
m_1u= (m_1+m_2)V

conservation of energy
1/2m_1u²=1/2m_1V² + 1/2m_2V²+1/2kx_max²

m_1u²-(m_1+m_2)V²=kx_max²

m_1u²- [(m_1u)²] / [m_1+m_2]=kx_max²

x_max=sqrt{m_1u²- [(m_1u)²] / [m_1+m_2]}/k