How do you solve #6y + 3( y - 9) = 4( y + 1) - 2#?

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Answer 1 · 2018-06-28T05:26:22

#y=29/5#

Given -

#6y+3(y-9)=4(y+1)-2#

Remove the brackets

#6y+3y-27=4y+4-2#

Simplify

#9y-27=4y+2#

Add #-4y# on both sides

#9y-27-4y=4y+2-4y#

#5y-27=cancel(4y)+2cancel(-4y)#

#5y-27=2#

Add #+27# to both sides

#5y-27+27=2+27#

#5ycancel(-27)cancel(+27)=2+27#

#5y=29#

#y=29/5#