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Find dy/dx using the rule dy/dx = dy/du•du/dx for y = log(ax+b)^3bassuming ax+b=u ?

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Jun 28, 2018

#dy/dx=(dy)/(du)*(du)/dx#

#y=log((ax+b)^3)#, #ax+b=u#, #(du)/dx=a#

#y=log(u^3)=3logu#

#color(blue)(d/dx)y=3color(blue)(d/dx)logu#

#dy/dx=3/u*(du)/dx=3/u*a=(3a)/(ax+b)#

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