How to solve the following using u-substitution. x^4+x^2+9=0?

1 Answer
Patrick H.
Jun 26, 2018

I'm not sure if you meant to type "substitution" as there needs to be two equations for that to be possible. However, using factoring, we can get our answer of #x=+-sqrt3#.

Explanation:

Let's factor our equation into a perfect square binomial , then set it equal to #0# and solve for #x#:

#x^4+x^2+9=0#
#(x^2+3)^2=0#
#x^2+3=0#
#x^2=3#
#x=+-sqrt3#

Hope this helped!!

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