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What is the equation of a circle with the center (3,1) and radius of 4?

1 Answer

Jun 25, 2018

#(x-3)^2+(y-1)^2=16#

Explanation:

The format for the equation of a circle is

#(x-h)^2+(y-k)^2=r^2#

where #(h,k)# is the center and #r# is the radius. We can just plug in values and solve from here:

#(x-3)^2+(y-1)^2=4^2#
#(x-3)^2+(y-1)^2=16#

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