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How to find dy/dx implicit differentiation? sin(x+y) + sin (x-y) = 1

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Jun 25, 2018

#cotxcoty=dy/dx#

Explanation:

#sin(a+b)+sin(a-b)=2sin(a)cos(b)#

Therefore our question simplifies to #2sinxcosy=1#

Implicit Differentiation using product rule

#2(cosxcosy-sinxsinydy/dx)=0#

#cosxcosy=sinxsinydy/dx#

#(cosxcosy)/(sinxsiny)=dy/dx#

#cotxcoty=dy/dx#

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