Please,why is MnO2-4 i.e manganese(vi)oxide not MnO3?...i still dont get it..i mean if u calculate the oxidation number with the latter it'll still be +6

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Answer 1 · 2018-06-24T02:08:34

The formula for manganese(VI) oxide is #MnO_3#

I'm not sure if I understand the question completely, but I'll verify the oxidation number and formula for #MnO_2# and #MnO_3#

We know that the oxidation number for O is -2
Let's set the oxidation number for Mn as x

Manganese(VI) oxide is indeed #MnO_3#

#Mn^"6+"# #O^"2-"# => #Mn_2O_6# => #MnO_3#

Oxidation number for Mn in #MnO_3#: x + 3(-2) = 0 => x = +6

Manganese(IV) oxide, on the other hand is #MnO_2#

#Mn^"4+"# #O^"2-"# => #Mn_2O_4# => #MnO_2#

Oxidation number for Mn in #MnO_2#: x + 2(-2) = 0 => x = +4