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How do you write the standard form of the equation of the circle with center (0,0) R=6?

1 Answer

Jun 22, 2018

#x^2+y^2=36#

Explanation:

If you know the coordinates of the center #(x_0, y_0)# and the radius #r# of a circle, the equation is

#(x-x_0)^2 + (y-y_0)^2 = r^2#

In your case, the center is #(x_0, y_0) = (0,0)# and the radius is #r=6#. So, the equation is

#(x-0)^2 + (y-0)^2 = 6^2#

which you can rewrite as

#x^2+y^2=36#

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