How do you divide #\frac { x ^ { 2} + 2x - 24} { 20- 5x } + \frac { x ^ { 2} + 4x - 12} { 2x + 4}#?

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Answer 1 · 2018-06-22T04:17:32

#(3x^2+4x-84)/(10x+20)#

#(x.(x+6)-4(x+6))/(-5(x-4))+(x^2+4x-12)/(2x+4)#

#((x-4)(x+6))/(-5(-4))+(x^2+4x-12)/(2x+4)#

#(x+6)/(-5)+(x^2+4x-12)/(2x+4)#

#-(x+6)/(5)+(x^2+4x-12)/(2x+4)#

#(-2(2x+4)(x+6)+5(x^2+4x-12))/(5(2x+4))#

#(-(2x^2+12x+4x+24)+5x^2+20x-60)/(10x+20)#

#(-2x^2-16x-24+5x^2+20x-60)/(10x+20)#

#(3x^2+4x-84)/(10x+20)#