How do you solve #2x+7=-7+x+6-x#?

Question

1347 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-21T20:05:10

#x = -4#

#2x + 7 = -7 + x + 6 - x#

Combine like terms on the right hand side of the equation:
#2x + 7 = -1#

Subtract #color(blue)7# from both sides:
#2x + 7 quadcolor(blue)(-quad7) = -1 quadcolor(blue)(-quad7)#

#2x = -8#

Divide both sides by #color(blue)2#:
#(2x)/color(blue)2 = (-8)/color(blue)2#

Therefore,
#x = -4#

Hope this helps!

Answer 2 · 2018-06-21T20:07:28

#x=-4#

It's a simple addition and subtraction problem all you have to do is to get the numbers on a side and terms containing #x# on the other side

#2x+7=-7+x+6-x#

#2x+7=-7+6cancel(+x-x)#

#2x+7=-1#

Subtract #7# from both sides

#2xcancel(+7-7)=-1-7#

#2x=-8#

Divide both sides by #2#

#x=-4#