Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve the following linear system: $4x-y=-4 , 3x+3y=-18$ ?

1 Answer

Jun 21, 2018

$x=-2$ and $y=-4$

Explanation:

$3*(4x-y)+3x+3y=3*(-4)+(-18)$

$12x-3y+3x+3y=(-12)+(-18)$

$15x=-30$ , so $x=-2$

Hence,

$4*(-2)-y=-4$

$-8-y=-4$

$y=(-8)-(-4)=-4$

Related questions

See all questions in Linear Systems with Addition or Subtraction

Impact of this question

1828 views around the world

You can reuse this answer
Creative Commons License