How can you write -2=log9 1/81 in exponential form?

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How can you write -2=log9 1/81 in exponential form?

write in exponential form

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Answer 1 · 2018-06-21T15:23:42

#9^-2=1/81#

Explanation:

The logarithm is defined as follows:
#log_b(a)=c# if and only if #a=b^c#.
Substituting #a=1/81#, #b=9#, and #c=-2#, we end up with this:
#log_9(1/81)=-2# if and only if #1/81=9^-2#.

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How can you write -2=log9 1/81 in exponential form?

write in exponential form

1 Answer

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